Given that \(\sin x = \frac{-\sqrt{3}}{2}\) and \(\cos x > 0\), find x.
FURTHER MATHEMATICS
WAEC 2012
Given that \(\sin x = \frac{-\sqrt{3}}{2}\) and \(\cos x > 0\), find x.
- A. 300°
- B. 240°
- C. 120°
- D. 60°
Correct Answer: A. 300°
Explanation
In order to do this, simply find the option in the range where only the cos is +ve. This occurs in the range \(270° \leq x \leq 360°\).
Check: \(\sin 300 = - \sin 60 = \frac{-\sqrt{3}}{2}\)
\(\cos 300 = \cos 60 = \frac{1}{2}\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *