Find \(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}\)
FURTHER MATHEMATICS
WAEC 2011
Find \(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}\)
- A. -1
- B. \(\frac{-1}{7}\)
- C. \(\frac{1}{7}\)
- D. 1
Correct Answer: A. -1
Explanation
\(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}\)
= \(\frac{6}{-6} = -1\)
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