Yomi was asked to label four seats S, R, P, Q. What is the probability...
FURTHER MATHEMATICS
WAEC 2010
Yomi was asked to label four seats S, R, P, Q. What is the probability he labelled them in alphabetical order?
- A. \(\frac{1}{24}\)
- B. \(\frac{1}{6}\)
- C. \(\frac{2}{13}\)
- D. \(\frac{1}{4}\)
Correct Answer: A. \(\frac{1}{24}\)
Explanation
The number of arrangements for the 4 letters = \(^{4}P_{4} = \frac{4!}{(4 - 4)!}\)
\(4! = 24\)
Alphabetical order is just 1 of the arrangements for the letters
= \(\frac{1}{24}\)
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