The table gives the distribution of marks of 60 candidates in a test. Marks 23-25

FURTHER MATHEMATICS
WAEC 2010

The table gives the distribution of marks of 60 candidates in a test.

Marks23-2526-2829-3132-3435-3738-40
Frequency371521104

(a) Draw a cumulative frequency curve of the distribution.

(b) From your curve, estimate the : (i) 80th percentile ; (ii) median ; (iii) semi-interquartile range.

Explanation

MarksFreqClass BoundariesCum. Freq
23 - 25322.5 - 25.53
26 - 28725.5 - 28.510
29 - 311528.5 - 31.525
32 - 342131.5 - 34.546
35 - 371034.5 - 37.556
38 - 40437.5 - 40.560

(a)

(b)(i) 80th percentile = \(\frac{80 \times 60th}{100} = \text{48th mark}\).

= 31.5.

(ii) Median = \(\frac{60th}{2} = \text{30th mark} = 32.3\)

(iii) Upper quartile = \(\frac{3 \times 60th}{4} = \text{45th mark} = 35.1\)

Lower quartile = \(\frac{60th}{4} = \text{15th mark} = 29.7\)

Semi-interquartile range = \(\frac{35.1 - 29.7}{2} = 2.7\)



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