In the diagram, a ladder PS leaning against a vertical wall PR makes angle x°...

FURTHER MATHEMATICS
WAEC 2009

In the diagram, a ladder PS leaning against a vertical wall PR makes angle x° with the horizontal floor. The ladder slides down to a point QT such that angle QTR = 30° and SNT = y°. Find an expression for tan y.

  • A. \(\frac{\sqrt{3} \tan x - 1}{\sqrt{3} + \tan x}\)
  • B. \(\frac{\sqrt{3} \tan x}{\sqrt{3} + \tan x}\)
  • C. \(\frac{\sqrt{3} \tan x + 1}{\sqrt{3} - \tan x}\)
  • D. \(\frac{3 \tan x - 1}{\sqrt{3} - \tan x}\)

Correct Answer: A. \(\frac{\sqrt{3} \tan x - 1}{\sqrt{3} + \tan x}\)



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.