Given that \(\log_{3}(x - y) = 1\) and \(\log_{3}(2x + y) = 2\), find the
FURTHER MATHEMATICS
WAEC 2009
Given that \(\log_{3}(x - y) = 1\) and \(\log_{3}(2x + y) = 2\), find the value of x.
- A. 1
- B. 2
- C. 3
- D. 4
Correct Answer: D. 4
Explanation
\(\log_{3}(x - y) = 1 \implies x - y = 3^{1} = 3 .... (1)\)
\(\log_{3}(2x + y) = 2 \implies 2x + y = 3^{2} = 9 ..... (2)\)
From (1), y = x - 3
From (2), y = 9 - 2x
\(\implies 9 - 2x = x - 3\)
\(9 + 3 = x + 2x = 3x\)
\(x = 4\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *