Find the value of p for which \(x^{2} - x + p\) becomes a perfect
FURTHER MATHEMATICS
WAEC 2007
Find the value of p for which \(x^{2} - x + p\) becomes a perfect square.
- A. \(-\frac{1}{2}\)
- B. \(\frac{1}{4}\)
- C. \(\frac{1}{2}\)
- D. \(1\)
Correct Answer: B. \(\frac{1}{4}\)
Explanation
The equation \(ax^{2} + bx + c\) is a perfect square if \(b^{2} = 4ac\).
\(x^{2} - x + p\)
\((-1)^{2} = 4(1)(p)\)
\(1 = 4p \implies p = \frac{1}{4}\)
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