2SO 2 (g) + O 2 (g) ↔ 2SO 3 (g) ΔH = -189 kJ
CHEMISTRY
JAMB 2001
2SO2(g) + O2(g) ↔ 2SO3(g) ΔH = -189 kJ mol-1 The equilibrium constant for the reaction above is increased by
- A. Increasing the temperature of the system
- B. Increase the pressure of the system
- C. The addition of a catalyst to the system
- D. Increasing the surface area of the vessel
Correct Answer: B. Increase the pressure of the system
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