A sugar solution was boiled with Fehling's solutions A and B and the colour remain...

Explanation

In this question, we are being asked to determine which type of sugar was tested based on its reaction with Fehling's solutions A and B. When a sugar solution is boiled with Fehling's solutions A and B, a red precipitate is formed if the sugar is a reducing sugar. However, if the sugar is not a reducing sugar, the colour of the solution remains blue. Out of the options given, glucose, fructose, maltose, and sucrose, only fructose is a reducing sugar. This means that if fructose is present in the sugar solution, it will react with Fehling's solutions A and B to form a red precipitate. Since the colour of the solution remained blue after boiling with Fehling's solutions A and B, we can conclude that the sugar tested was not a reducing sugar. Therefore, the correct answer is option C, fructose. It is important to note that glucose and maltose are also reducing sugars, but they were not the correct answer in this case. Additionally, sucrose is a non-reducing sugar, which means it will not react with Fehling's solutions A and B to form a red precipitate. Overall, this question tests our understanding of the properties of different types of sugars and their reactions with Fehling's solutions A and B.