When an alternating current given by I = 10sin (120π)t passes through a 12Ω resistor,
PHYSICS
JAMB 2003
When an alternating current given by I = 10sin (120π)t passes through a 12Ω resistor, the power dissipated in the resistor is
- A. 1200W
- B. 600W
- C. 120W
- D. 30W
Correct Answer: A. 1200W
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
1200W is the answer, pls check explanation below
Explanation
An a.c current is usually expressed as I = Io sin wt; and comparing this with the given current I = 10sin (120?)t, => Io = 10.
and power in an a.c circuit is given as:
P = I2R
= (102 x 12)
= 1200W