(a) Convert the following numbers to be stated bases: (i) 125.625, to binary (ii) 111011.10011,

COMPUTER
WAEC 2016

(a) Convert the following numbers to be stated bases:

(i) 125.625, to binary

(ii) 111011.10011, to octal

(b) Given that X = 11011011 and Y= 11101101,

(i) construct the truth table for X, Y Z;

(ii) draw the logic gate of X, Y = Z

(iii) state the value of Z.

Explanation

(a)) 125.625, to binary

2125R
2621
2310
2151
271
231
211
201

Therefore, 125= 111110

Hence, 125.625 = 1111101.101,

2nd step: 125 to binary

First method: (0.625) = 625/1000 = 25/40 = 5/8

Hence, 5/8 = (4+1)/ 8 = 4/8 + 1/8 = 1/2 + 1/8

1 X 2\(^{-1}\) + 0 X 2 \(^{-2}\) + 1 x 2\(^{-3}\) = 0.101\(_{-2}\)

Therefore, 0.625 = 0.101\(_{-2}\),

Second method: 0.625*2 = 1.25 Fraction part 1.23 Carry1

0.25 * 2 =0.5 Fraction part 0.5 Carry 0

0.5 * 2 = 1.00 Fraction part 1.00 Cary 1

0.625 = 0.101\(_{-2}\),

Therefore, (i) 111011.10011, to octal

111\(_2\) = 7\(_8\)

011\(_2\) = 3\(_8\)

100\(_2\) = 4\(_8\)

110\(_2\) = 6\(_8\)

111011.10011\(_2\) = 73.46\(_8\)



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