In an electric circuit, an inductor of inductance 0.5 H and resistance 50 Ω is
PHYSICS
WAEC 2020
In an electric circuit, an inductor of inductance 0.5 H and resistance 50 Ω is connected to an alternating current source of frequency 60 Hz. Calculate the impedance of the circuit.
- A. 50.0 Ω
- B. 450.5 Ω
- C. 195.0 Ω
- D. 1950.1 Ω
Correct Answer: C. 195.0 Ω
Explanation
The impedance of a R-L circuit is given by:
Z = √(R\(^2\) + XL\(^2\)) ----------- eqn(1)
where Z is the impedance,
R is the resistance, and
XL is the inductive reactance
XL = 2πfL ------------ eqn(2)
where f is the frequency
From eqn(2),
XL = 2 * π * 60 * 0.5
= 60π
Also, from eqn(1),
Z = √(50\(^2\) + (60π)\(^2\))
Z = 195.0Ω
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