Two bodies of masses 3.0 kg and 2.0 kg are separated by a distance of
PHYSICS
WAEC 2019
Two bodies of masses 3.0 kg and 2.0 kg are separated by a distance of 50 cm. Calculate the force of attraction between them. [G = 6.67 x 10\(^{-11}\) Nm\(^2\) kg\(^2\)]
- A. 1.6 x 10\(^{-9}\)N
- B. 1.3 x 10\(^{3}\)N
- C. 2.3 x 10\(^{3}\)N
- D. 5.0x 10\(^{3}\)N
Correct Answer: A. 1.6 x 10\(^{-9}\)N
Explanation
Using the formula
F = \(\frac{Gm_1m_2}{r^2}\)
= \(\frac{6.67 \times 10^{-11} \times 3.0 \times 2.0}{(50)^2}\)
= \(\frac{40.02 \times 10^{-11}}{2500}\)
= 1.6 x 10\(^{-9}\)N
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