Two capacitors, each of capacitance 2\(\mu\)F are connected in parallel. If the p.d across them...
PHYSICS
WAEC 2012
Two capacitors, each of capacitance 2\(\mu\)F are connected in parallel. If the p.d across them is 120V, calculate the charge on each capacitor
- A. 6.0 x 10-5C
- B. 1.2 x 10-4C
- C. 2.4 x 10-4C
- D. 4.8 x 10-4C
Correct Answer: C. 2.4 x 10-4C
Explanation
C = \(C_1 + C_2 = 2 + 2 = 4 \mu F\)
but Q = CV
= 4 x 10\(^{-6}\) x 120
= 4.8 x 10\(^{-4}\)
\(\therefore\) Each of the capacitor has a charge of \(\frac{4.8 \times 10^{-4}}{2}\)
= 2.4 x 10\(^{-4}\) C
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