A block of wood of density 0.6 gcm\(^{-3}\), weighing 3.06N in air, floats freely in...
PHYSICS
WAEC 2012
A block of wood of density 0.6 gcm\(^{-3}\), weighing 3.06N in air, floats freely in a liquid of density 0.9 gcm\(^{-3}\). Calculate volume of the portion immersed (g = 10ms\(^{-2}\))
- A. 510cm3
- B. 340cm3
- C. 254cm3
- D. 170cm3
Correct Answer: B. 340cm3
Explanation
V = \(\frac{M}{D}\)
= \(\frac{3.06}{10} \times \frac{1000}{0.9} = 340\)
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