simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed...
PHYSICS
WAEC 2010
simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
- A. 125\(\pi\)
- B. 25.00\(\pi\)
- C. 100.00 \(\pi\)
- D. 400.00\(\pi\)
Correct Answer: B. 25.00\(\pi\)
Explanation
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *