A cell of e.m.f. 1.5V is connected in series with a resistor of resistance 3.0\(\Omega\)....
PHYSICS
WAEC 2009
A cell of e.m.f. 1.5V is connected in series with a resistor of resistance 3.0\(\Omega\). A voltmeter connected across the cell registers 0.9V. Calculate the internal resistance of the cell
- A. 2.0\(\Omega\).
- B. 3.0\(\Omega\).
- C. 5.0\(\Omega\).
- D. 6.0\(\Omega\).
Correct Answer: A. 2.0\(\Omega\).
Explanation
\(\frac{V}{R} = \frac{E}{R + r}\)
\(\frac{0.9}{3} = \frac{1.5}{3 + r}\)
r = 2\(\Omega\).
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *