A body of volume 0.046m 3 is immersed in a liquid of density 980kgm -3
PHYSICS
WAEC 2009
A body of volume 0.046m3 is immersed in a liquid of density 980kgm-3 with \(\frac{3}{4}\) of its volume submerged. Calculate the upthrust on the body. [g = 10ms-2]
- A. 11.27N
- B. 33.81N
- C. 112.70N
- D. 338.10N
Correct Answer: D. 338.10N
Explanation
M = D x V
= 980 x 0.046 x \(\frac{3}{4}\) = 33.81kg
upthrust = mg = 33.81 x 10
= 338.1N
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