Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the...
PHYSICS
WAEC 2008
Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[\(\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}\)]
- A. 1.44 x 10-7N
- B. 7.20 x 10-9N
- C. 7.20 x 10-11N
- D. 1.44 x 1011N
Correct Answer: A. 1.44 x 10-7N
Explanation
f = \(\frac{1}{4 \pi \mathit{E}_o} \times \frac{Q^2}{r^2} = \frac{9 \times 10^9(2 \times 10^{-2})^2}{(0.05)^2}\)
= 1.44 x 10-2N
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