A body is projected at an angle of 30° to the horizontal with a velocity...
PHYSICS
WAEC 2015
A body is projected at an angle of 30° to the horizontal with a velocity of 150 ms\(^{-1.}\). Calculate the time it takes to reach the greatest height [Take g = 10 ms\(^2\) and neglect air resistance]
Explanation
Given Data: u = 150 ms\(^{-1.}\), Ø = 30°
Time of Flight = \(\frac{2usinØ}{g}\) → \(\frac{2 * 150 * sin30°}{10}\)
= 15s
t = time taken to reach maximum height = ?
t = usinθ÷g
t = [150 × sin(30)] ÷10
t = 7.5secs.
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *