A stone is projected vertically upward with a speed of 30ms\(^{1}\) from the top of...
PHYSICS
WAEC 2010
A stone is projected vertically upward with a speed of 30ms\(^{1}\) from the top of a tower of height 50 m. Neglecting air resistance, determine the maximum height it reached from the ground. [g = 10 ms\(^-2\)]
Explanation
V\(^2 = U^2 - 2gs\)
S = \(\frac{V^2 - U^2}{-2g} = \frac{O^2 - 30^2}{-2 \times 10}\) = 45m
Height from ground = 50 + 45 = 95m
Height from ground = 50 + 45 = 95m
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