Water of mass 120g at 50°C is added to 200g of water at 10°C and...
PHYSICS
WAEC 2002
Water of mass 120g at 50°C is added to 200g of water at 10°C and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
- A. 60oC
- B. 40oC
- C. 25oC
- D. 10oC
Correct Answer: C. 25oC
Explanation
120 x 4.2(50 - \(\theta\)) = 200 x 4.2(\(\theta\) - 10)
\(\theta = \frac{33600}{1344} = 25^oC\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *