The energy stored in a capacitor of capacitance 5?F is 40J. Calculate the voltage applied...
PHYSICS
WAEC 1995
The energy stored in a capacitor of capacitance 5?F is 40J. Calculate the voltage applied across its terminals? The energy stored in a capacitor of capacitance 5μF is 40J. Calculate the voltage applied across its terminals?
- A. 4000V
- B. 200V
- C. 16V
- D. 6V
Correct Answer: A. 4000V
Explanation
\(E = \frac{CV^{2}}{2}\)
\(V^{2} = \frac{2E}{C}\)
\(V^{2} = \frac{2\times 40}{5 \times 10^{-6}}\)
\(V^{2} = 16 \times 10^{6}\)
\(V = 4 \times 10^{3} = 4000v\)
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