A metal rod of length 40cm at 20°C is heated to a temperature of 45°C....
PHYSICS
WAEC 1994
A metal rod of length 40cm at 20°C is heated to a temperature of 45°C. If the new length of the rod is 40.05cm. Calculate its linear expansitivity
- A. 1.2 x \(10^{-5}K^{-1}\)
- B. 2.5x \(10^{-5}K^{-1}\)
- C. 3.5x \(10^{-5}K^{-1}\)
- D. 5x \(10^{-5}K^{-1}\)
Correct Answer: D. 5x \(10^{-5}K^{-1}\)
Explanation
\(\alpha = \frac{I_2-I_1}{I_1(\theta_2-\theta_1)} \\ \Rightarrow \frac{40.05 - 40}{40 \times (45-20)} = 5.0 \times10^{-5}\)
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