A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T....
PHYSICS
WAEC 1993
A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms-2, calculate the magnitude of the force exerted on the particle
- A. 0.050 N
- B. 0.075N
- C. 0.0300N
- D. 3.300N
Correct Answer: B. 0.075N
Explanation
F = eV = 0.01 x 5 x 1.5 = 0.075N
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