A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series...
PHYSICS
WAEC 1990
A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
- A. 0.15 A
- B. 0.20 A
- C. 0.60A
- D. 3.00A
Correct Answer: A. 0.15 A
Explanation
I = E/R + r = 1.5/2.5 + 0.5 + 7 = 0.15
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