Given that y =(\(\frac{pr}{m} - p^2r\))\(^{\frac{-3}{2}}\) (a) make r the subject; (b) find the value...

Explanation

(a) y =(\(\frac{pr}{m} - p^2r\))\(^{\frac{-3}{2}}\)

y\(^{\frac{-2}{3}}\) =(\(\frac{pr}{m} - p^r2\))

my\(^{\frac{-2}{3}}\) =(\(\frac{pr- p^r2m}{m}\))

my\(^{\frac{-2}{3}}\) = pr - p\(^2\)rm

my\(^{\frac{-2}{3}}\) = r(p - p\(^2\)m)

r = (\(\frac{my^{-2/3}}{m - p^2m}\))

(b) r = (\(\frac{1-8^{-2/3}}{3 - 3^2 * 1}\))

= \(\frac{1}{4}\) ÷ -6

= - \(\frac{1}{-6}\)

= - \(\frac{1}{24}\)