(a) Ali and Yusif shared N420.000.00 in the ratio 3.,; 5 : 8 respectively. Find
MATHEMATICS
WAEC 2019
(a) Ali and Yusif shared N420.000.00 in the ratio 3.,; 5 : 8 respectively. Find the sum of Ali and Yusuf's shares
(b) Solve: 2(\(\frac{1}{8}\))\(^x\) = 32\(^{x - 1}\).
Explanation
Total ratio = 3 + 5 + 8 = 26
Ali's share is \(\frac{3}{16}\) x N420,000
= N78,000
Yusuf's share is \(\frac{8}{16}\) x N420,000
= N210,000
Sum of Ali's share + Yusuf's share
= N78,750 + N210,000
= N288,750
(b) 2(\(\frac{1}{8}\))\(^2\) = 32\(^{x - 1}\)
2\(^{1}\) x 2\(^{3x}\) = 2\(^{5x - 5}\)
2\(^{1 - 3x}\) = 2\(^{5x - 5}\)
1 - 3x = 5x - 5
-3x - 5x = -5 -1
-8x = -6
x = \(\frac{-6}{-8}\)
= \(\frac{3}{4}\)
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