(a) Copy and complete the table of values for the relation y = 4x\(^2\) -

MATHEMATICS
WAEC 2019

(a) Copy and complete the table of values for the relation y = 4x\(^2\) - 8x - 21, for -2.0 \(\leq\) x \(\leq\) 4.0

x-2.0-1.5-1.00.50.00.51.0 1.52.02.53.03.54.0
y11-9-21-24-21-90

(b) Using a scale of 2cm to 1 unit on the x-axis and 2cm to 5 units on the y-axis, draw the graph for the relation y = 4x\(^2\) - 8x - 21

(ii) Use the graph to find the solution set of

(\(\alpha\)) 4x\(^2\) - 8x = 3;

(\(\beta\)) 4x\(^2\) - 7x - 21 = 0

Explanation

(a) They completed the table of values as shown

x-2.0-1.5-1.00.50.00.51.0 1.52.02.53.03.54.0
y110-9-16-21-24-25-24-21-16-9011

(b)(i) The graph

(b)(ii)(\(\alpha\), deduce that 4x\(^2\) - 8x - 21 = 3 - 21 so that y = -18. From the graph, the point of intersection of y = -18 and y = 4x\(^2\) - 8x - 21 was atx = {-0.35 \(\pm\) 0.1, 2.3 \(\pm\) 0.1}

(b)(ii)(\(\beta\)), the equation 4x\(^2\) - 8x - 21 = 0 which can be written as 4x\(^2\) - x - 7x - 21 = -x. This implies that 4x\(^2\) - 8x - 21 = -x.

But, y = 4x\(^2\) - 8x - 21 so that y = -x, Next was to draw the line y = -x and from the graph, the point of intersection with the curve y = 4x\(^2\) - 8x - 21 was at x = {3.3 \(\pm\) 0.1, -1.6 \(\pm\) 0.1}



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