(a) Solve : \(7x + 4 < \frac{1}{2}(4x + 3)\). (b) Salem, Sunday and Shaka
(a) Solve : \(7x + 4 < \frac{1}{2}(4x + 3)\).
(b) Salem, Sunday and Shaka shared a sum of N1,100.00. For every N2.00 that Salem gets, Sunday gets 50 kobo and for every N4.00 Sunday gets, Shaka gets N2.00. Find Shaka's share.
Explanation
(a) \(7x + 4 < \frac{1}{2}(4x + 3)\)
\(7x + 4 < 2x + \frac{3}{2}\)
\(7x - 2x < \frac{3}{2} - 4\)
\(5x < -\frac{5}{2}\)
\(\frac{5x}{5} < \frac{-\frac{5}{2}}{5}\)
\(x < -\frac{1}{2}\).
(b) When Salem gets N2 ------> Sunday gets 50 kobo
(Recall N1 = 100 kobo)
Salem gets 200 kobo ------> Sunday gets 50 kobo.
Sunday gets N4 -----> Shaka gets N2.
====> Sunday gets 400 kobo ------> Shaka gets 200 kobo.
When Sunday gets 400 kobo ------> Salem gets 1600 kobo.
\(\therefore\) Salem : Sunday : Shaka = 1600 : 400 : 200
= 8 : 2 : 1
\(\therefore \text{Shaka's share} = \frac{1}{11} \times N1,100 = N100\)