(a) In the diagram, AOB is a straight line. < AOC = 3(x + y)°,

MATHEMATICS
WAEC 2007

(a)bearing and distance

In the diagram, AOB is a straight line. < AOC = 3(x + y)°, < COB = 45°, < AOD = (5x + y)° and < DOB = y°. Find the values of x and y.

(b) From two points on opposite sides of a pole 33m high, the angles of elevation of the top of the pole are 53° and 67°. If the two points and the base are on te same horizontal level, calculate, correct to three significant figures, the distance between the two points.

Explanation

(a) \(3(x + y) + 45 = 180°\) ( sum of angles on a straight line)

\(3x + 3y + 45 = 180 \implies 3x + 3y = 135\)

\(3x = 135 - 3y \implies x = 45 - y\)

Also,

\(5x + y + y = 180\)

\(5x + 2y = 180..... (*)\)

Put x = 45 - y into (*) above,

\(5(45 - y) + 2y = 180 \implies 225 - 5y + 2y = 180\)

\(225 - 3y = 180 \implies 3y = 45\)

\(y = \frac{45}{3} = 15°\)

\(x = 45 - y\)

\(x = 45 - 15 = 30°\)

(b)triangle

Let the distance BD = x and CD = y.

In \(\Delta ABD\),

\(\tan 53 = \frac{33}{x}\)

\(x = \frac{33}{\tan 53}\)

= \( 24.868 cm\)

In \(\Delta ACD\),

\(\tan 67 = \frac{33}{y}\)

\(y = \frac{33}{\tan 67}\)

\(y = 14.01 cm\)

\(\therefore BC = x + y \)

\(24.868 + 14.01 = 38.878 cm\)

\(\approxeq 38.9 cm\)



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