The table below shows the values of the relation \(y = 11 - 2x -

MATHEMATICS
WAEC 2003

The table below shows the values of the relation \(y = 11 - 2x - 2x^{2}\) for \(-4 \leq x \leq 3\).

x-4-3-2-10123
y-1311

(a) Copy and complete the table.

(b) Using a scale of 2 cm to 1 unit on the x- axis and 2 cm to 5 units on the y- axis, draw the graph of \(y = 11 - 2x - 2x^{2}\).

(c) Use your graph to find : (i) the roots of the equation \(11 - 2x - 2x^{2} = 0\) ; (ii) the values of x for which \(3 - 2x - 2x^{2} = 0\) ; (iii) the gradient of the curve at x = 1.

Explanation

(a)

x-4-3-2-10123
\(x^{2}\)169410149
\(11\)1111111111111111
\(-2x\)86420-2-4-6
\(-2x^{2}\)-32-18-8-20-2-8-18
y-13-1711117-1-13

(b)graph

(c)(i) x = -2.9 or 1.9

(ii) \(y + (3 - 2x - 2x^{2}) = 11 - 2x - 2x^{2}\)

\(y = 11 - 2x - 2x^{2} - 3 + 2x + 2x^{2}\)

\(y = 8\)

\(\therefore x = \text{-1.8 or 0.8}\)

(iii) \(y = 11 - 2x - 2x^{2}\)

\(\frac{\mathrm d y}{\mathrm d x} = -2 - 4x\)

Gradient at x = 1 : \(-2 - 4(1) = -2 - 4 = -6\)



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