The solid is a cylinder surmounted by a hemispherical bowl. Calculate its (a) total surface...

MATHEMATICS
WAEC 1997

area of cylinder The solid is a cylinder surmounted by a hemispherical bowl. Calculate its

(a) total surface area ;

(b) volume (Take \(\pi = \frac{22}{7}\))

Explanation

(a) Area of curved surface of cylinder = \(2\pi r h\)

= \(2 \times \frac{22}{7} \times 7 \times 10cm^{2} = 440 cm^{2}\)

Area of the base of cylinder = \(\pi r^{2}\)

= \(\frac{22}{7} \times 7 \times 7 = 154 cm^{2}\)

Surface area of hemisphere = \(\frac{4\pi r^{2}}{2} = 2 \pi r^{2}\)

= \(2 \times \frac{22}{7} \times 7 \times 7 = 308 cm^{2}\)

\(\therefore\) Total surface area = 440 + 154 + 308 = 902cm\(^{2}\)

(b) Volume of cylinder = \(\pi r^{2} h\)

= \(\frac{22}{7} \times 7 \times 7 \times 10 = 1540 cm^{3}\)

Volume of hemisphere = \(\frac{1}{2}(\frac{4\pi r^{3}}{3})\)

= \(\frac{4 \times 22 \times 7 \times 7 \times 7}{2 \times 7 \times 3}\)

= \(718.67 cm^{3}\)

Total volume = 1540 + 718.67 = 2258.67 cm\(^{3}\).



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