make u the subject in x =\(\frac{2u-3}{3u + 2}\)
MATHEMATICS
WAEC 2021
make u the subject in x =\(\frac{2u-3}{3u + 2}\)
- A. u = \(\frac{2x + 3}{3x - 2}\)
- B. u = \(\frac{2x - 3}{3x - 2}\)
- C. u = \(\frac{2x + 3}{2 - 3x}\)
- D. u = \(\frac{2x + 3}{3x + 2}\)
Correct Answer: C. u = \(\frac{2x + 3}{2 - 3x}\)
Explanation
x =\(\frac{2u-3}{3u + 2}\)
cross multiply
x(3u + 2) = 2u - 3
3ux + 2x = 2u - 3
collect like terms of u
2x + 3 = 2u - 3ux
\(\frac{2x + 3}{2 - 3x}\) = u
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