If 16 × 2\(^{(x + 1)}\) = 4\(^x\) × 8\(^{(1 - x)}\), find the value
MATHEMATICS
WAEC 2021
If 16 × 2\(^{(x + 1)}\) = 4\(^x\) × 8\(^{(1 - x)}\), find the value of x.
- A. -4
- B. 4
- C. 1
- D. -1
Correct Answer: D. -1
Explanation
16 * 2\(^{(x + 1)}\) = 4\(^x\) * 8\(^{(1 - x)}\)
= 2\(^4\) * 2\(^{(x + 1)}\) = 2\(^{2x}\) * 2\(^{3(1 - x)}\)
--> 4 + x + 1 = 2x + 3 - 3x
collect like terms
--> x - 2x + 3x = 3 - 1 - 4
--> 2x = -2
--> x = -1
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