In the diagram, \(\overline{MN}\)//\(\overline{PQ}\), < MNP = 2x, and < NPQ = (3x - 50)°....
MATHEMATICS
WAEC 2020
In the diagram, \(\overline{MN}\)//\(\overline{PQ}\), < MNP = 2x, and < NPQ = (3x - 50)°. Find the value of < NPQ
- A. 200\(^o\)
- B. 100\(^o\)
- C. 120\(^o\)
- D. 90\(^o\)
Correct Answer: B. 100\(^o\)
Explanation
2x = 3x - 50 alternate angle
50\(^o\) = 3x - 2x
50\(^o\) = x
< NPQ = (3x - 50)\(^o\)
= 3(500)\(^o\) - 50
= 150 - 50 = 100\(^o\)
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