Find the equation of the line parallel to 2y = 3(x - 2) and passes
MATHEMATICS
WAEC 2020
Find the equation of the line parallel to 2y = 3(x - 2) and passes through the point (2, 3)
- A. y = \(\frac{2}{3} x - 3\)
- B. y = \(\frac{2}{3} x - 2\)
- C. y = \(\frac{2}{3} x\)
- D. y = \(\frac{-2}{3} x\)
Correct Answer: C. y = \(\frac{2}{3} x\)
Explanation
2y = 3(x - 2)
\(\frac{2y}{2} = \frac{3x}{2} - \frac{6}{2}\)
y = \(\frac{3}{2}x - 3\)
m = \(\frac{3}{2}\)
\(\frac{y - y_1}{x - x_1}\) = m
\(\frac{y - 3}{x - 2} = \frac{3}{2}\)
2y - 6 = 3x - 6
\(\frac{2y}{2} = \frac{3x}{2}\)
y = \(\frac{3}{2}\)x
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *