Solve 4x\{^2}\) - 16x + 15 = 0.
MATHEMATICS
WAEC 2019
Solve 4x\{^2}\) - 16x + 15 = 0.
- A. x = 1\(\frac{1}{2}\) or x = -2\(\frac{1}{2}\)
- B. x = 1\(\frac{1}{2}\) or x = 2\(\frac{1}{2}\)
- C. x = 1\(\frac{1}{2}\) or x = -1\(\frac{1}{2}\)
- D. x = -1\(\frac{1}{2}\) or x -2\(\frac{1}{2}\)
Correct Answer: B. x = 1\(\frac{1}{2}\) or x = 2\(\frac{1}{2}\)
Explanation
4x\(^2\) - 16x + 15 = 0
(2x - 3)(2x - 5) = 0
x = 1\(\frac{1}{2}\) or x = 2\(\frac{1}{2}\)
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