The roots of a quadratic equation are \(\frac{-1}{2}\) and \(\frac{2}{3}\). Find the equation.
MATHEMATICS
WAEC 2017
The roots of a quadratic equation are \(\frac{-1}{2}\) and \(\frac{2}{3}\). Find the equation.
- A. \(6x^2 - x + 2 = 0\)
- B. \(6x^2 - x - 2 = 0\)
- C. \(6x^2 + x - 2 = 0\)
- D. \(6x^2 + x + 2 = 0\)
Correct Answer: B. \(6x^2 - x - 2 = 0\)
Explanation
(x + \(\frac{1}{2}\)) (n - \(\frac{2}{3}\))
\(x^2 - \frac{2}{3^x} + \frac{x}{2} - \frac{1}{3}\)
\(6x^2 - 4n + 3n - 2 = 0\)
\(6x^2 - x - 2 = 0\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *