In the diagram, O is the centre, \(\bar{RT}\) is a diameter, ∠PQT = 33° and...
MATHEMATICS
WAEC 2015
In the diagram, O is the centre, \(\bar{RT}\) is a diameter, ∠PQT = 33° and ∠TOS = 76°. Using the diagram, calculate the value of angle PTR
- A. 73°
- B. 67°
- C. 57°
- D. 37°
Correct Answer: C. 57°
Explanation
In the diagram given, < PRT = 3\(^o\) (Change in same segment)
< TPR = 90\(^o\) (angle in a semicircle)
Hence, < PTR = 180\(^o\) - (90 + 33)\(^o\)
= 180\(^o\) - 123\(^o\)
= 57\(^o\)
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