Express \(\frac{2}{x + 3} - \frac{1}{x - 2}\) as a simple fraction
MATHEMATICS
WAEC 2013
Express \(\frac{2}{x + 3} - \frac{1}{x - 2}\) as a simple fraction
- A. \(\frac{x - 7}{x^2 + x - 6}\)
- B. \(\frac{x - 1}{x^2 + x - 6}\)
- C. \(\frac{x - 2}{x^2 + x - 6}\)
- D. \(\frac{x - 27}{x^2 + x - 6}\)
Correct Answer: A. \(\frac{x - 7}{x^2 + x - 6}\)
Explanation
\(\frac{2}{x + 3} - \frac{1}{x - 2}\) = \(\frac{2(x - 2) - (x - 3)}{(x + 3) (x - 2)}\)
= \(\frac{2x - 4 - x - 3}{x^2 - 2x + 3x - 6}\)
= \(\frac{x -7}{x^2 + x - 6}\)
= \(\frac{x - 7}{x^2 + x - 6}\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *