Given that p \(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation...
MATHEMATICS
WAEC 2013
Given that p\(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\), make q the subject of the equation
- A. q = p\(\sqrt{r}\)
- B. q = p3r
- C. q = pr3
- D. q = pr\(\frac{1}{3}\)
Correct Answer: D. q = pr\(\frac{1}{3}\)
Explanation
p\(\frac{1}{3}\) = \(\frac{3\sqrt{q}}{r}\)(cross multiply)
3\(\sqrt{q}\) = r x 3\(\frac{\sqrt{q}}{r}\)(cross multiply)
3\(\sqrt{q}\) = r x 3\(\sqrt{p}\) cube root both side
q = 3\(\sqrt{r}\) x p
q = r\(\frac{1}{3}\)p = pr\(\frac{1}{3}\)
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