A bag contains 4 red and 6 black balls of the same size. If the
MATHEMATICS
WAEC 2012
A bag contains 4 red and 6 black balls of the same size. If the balls are shuffled briskly and two balls are drawn one after the other without replacement, find the probability of picking balls of different colours
- A. \(\frac{8}{15}\)
- B. \(\frac{13}{25}\)
- C. \(\frac{11}{15}\)
- D. \(\frac{13}{15}\)
Correct Answer: A. \(\frac{8}{15}\)
Explanation
Prob(RB + BR) = Total balls = 4 + 6 = 10
= prob(\(\frac{4}{10} \times \frac{6}{9}\)) + prob(\(\frac{6}{10} \times \frac{4}{9}) = \frac{24}{90} + \frac{24}{90}\)
= \(\frac{48}{90} = \frac{16}{30} = \frac{8}{15}\)
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