\(\begin{array}{c|c} x & 0 & 2 & 4 & 6\\ \hline y & 1 &
MATHEMATICS
WAEC 2010
\(\begin{array}{c|c} x & 0 & 2 & 4 & 6\\ \hline y & 1 & 2 & 3 & 4\end{array}\).
The table is for the relation y = mx + c where m and c are constants. What is the equation of the line described in the tablet?
- A. y = 2x
- B. y = x + 1
- C. y = x
- D. y = \(\frac{1}{2}x + 1\)
Correct Answer: D. y = \(\frac{1}{2}x + 1\)
Explanation
y = mx + c; when x = 0; y = 1
1 = m(0) + c; 1 = 0 + c; c = 1
when x = 2; y = 2
2 = m(2) + c; 2 = 2m + c; but c = 1
2 = 2m + 1
2 - 1 = 2m
2m = 1
m = \(\frac{1}{2}\)
y = \(\frac{1}{2}\)x + 1
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *