Solve the inequality: 3(x + 1) \(\leq\) 5(x + 2) + 15
MATHEMATICS
WAEC 2010
Solve the inequality: 3(x + 1) \(\leq\) 5(x + 2) + 15
- A. x \(\geq\) -14
- B. x \(\leq\) - 14
- C. x \(\geq\) -11
- D. x \(\leq\) - 11
Correct Answer: D. x \(\leq\) - 11
Explanation
3(x + 1) \(\leq\) 5(x + 2) + 15
3x + 3 \(\leq\) 5x + 10 + 15
3x - 5x \(\geq\) 10 + 15 - 3
-2x \(\geq\) 22
x \(\leq\) \(\frac{-22}{2}\)
x \(\leq\) -11
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *