In the diagram, IG is parallel to JE, JEF = 120° and FHG = 130°,

MATHEMATICS

WAEC 2009

In the diagram, IG is parallel to JE, JEF = 120° and FHG = 130°, find the angle marked t

A. 40°
B. 70°
C. 80°
D. 100°

Correct Answer: B. 70°

Explanation

Now, t + 60^o + 50^o = 180^o

t = 180^o - 110^o

t = 70^o

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