solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
MATHEMATICS
WAEC 2009
solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
- A. 1
- B. \(\frac{1}{5}\)
- C. -\(\frac{1}{5}\)
- D. -1
Correct Answer: A. 1
Explanation
\(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1
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