In the diagram, PR is a diameter of the circle centre O. RS is a...
MATHEMATICS
WAEC 2006
In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58o. Find ∠QRS
- A. 112o
- B. 116o
- C. 122o
- D. 148o
Correct Answer: C. 122o
Explanation
PRQ = 90 - 58 = 32o(angle in a semi-circle)
Since PRS = 90o(radius angular to tangent)
QRS = 90 + 32
= 122o
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