If p = [\(\frac{Q(R - T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation...
MATHEMATICS
WAEC 2006
If p = [\(\frac{Q(R - T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation
- A. T = R + \(\frac{P^3}{15Q}\)
- B. T = R - \(\frac{15P^3}{Q}\)
- C. T = R + \(\frac{P^3}{15Q}\)
- D. T = 15R - \(\frac{Q}{P^3}\)
Correct Answer: B. T = R - \(\frac{15P^3}{Q}\)
Explanation
Cubic both sides; P3 = \(\frac{Q(R - T)}{15}\)
(cross multiplication) Q(R - T) = 15P3
(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)
(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)
T = R - \(\frac{15P^3}{Q}\)
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