\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1
MATHEMATICS
WAEC 2006
\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table below satisfies the relation y - k\(\sqrt{x}\), where k is a positive constant. Find the value of P,
- A. 2
- B. 4
- C. 10
- D. 25
Correct Answer: D. 25
Explanation
From y = \(\frac{1}{2} \sqrt{x}\)
when y = 2.5 or \(\frac{5}{2}\), x = P
\(\frac{5}{2} \times \frac{1}{2} \sqrt{P}\)
\(\sqrt{P} = \frac{10}{2} = 5\)
P = 52
= 25
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